3v^2+3v-10=0

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Solution for 3v^2+3v-10=0 equation: 



3v^2+3v-10=0

a = 3; b = 3; c = -10;
Δ = b2-4ac
Δ = 32-4·3·(-10)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{129}}{2*3}=\frac{-3-\sqrt{129}}{6}
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{129}}{2*3}=\frac{-3+\sqrt{129}}{6}
$

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